(sin(x))^2+2*cos(x)sin(x)+(cos(x))=1 решите пж

(sin(x))^2+2*cos(x)sin(x)+(cos(x))=1 (sin(x))^2+ sin2x+cosx = 1 (sin(x))^2 + sin2x + cosx = (sin(x))^2 + (cos(x))^2 sin2x + cosx = cos(x))^2 cos(x))^2 - cosx = sin2x cosx (cosx - 1) = sin2x