решите уравнение cos2x+7sinx+3=0

(1 - 2sin²x) + 7sinx + 3 = 02sin²x - 7sinx - 4 = 0sinx = (7 ± √(49+32))/4 = (7±9)/4 = {4; -½}sinx = 4 - бредsinx = -½x = -π/6 + 2πnx = -5π/6 + 2πkn,k ∈ ℤОтвет: x = -π/6 + 2πn или х = -5π/6 + 2πk, n,k ∈ ℤ