помогите решить пример 4 целых 1/3 * (5/6+0.25)*3,6*(7/12+1/9)*(7/12-2/15) разделить 0,9*(5/8-1/3)*1целая5/74_1/3 * (5/6+0.25)*3,6*(7/12+1/9)*(7/12-2/15) /(0,9*(5/8-1/3)*1_5/7)==(13/3) * (5/6+0.25)*3,6*(7/12+1/9)*(7/12-2/15) /(0,9*(5/8-1/3)*(12/7))=(13/3) * (5/6+1/4)*(18/5)*(7/12+1/9)*(7/12-2/15) /(0,9*(5/8-1/3)*(12/7))==(13/3) * (13/12)*(18/5)*(25/36)*(27/60) /(0,9*(7/2)*(1/7))==13*(13/4)*(1/4)*(1/2) /((9/10)*(7/2)*(1/7))==((13*13*1*1)/(4*4*2)) /((9*7*1)/(10*2*7))==(169/32) /(63/140)==(169*140)/(32*63)==(169*35)/(8*63)==(169*5)/(8*9)==845/72 = 11_53/72 (11 целых и 53/72)Если задание выглядит так:(4_1/3)/(5/6+0.25)*3,6*(7/12+1/9)*(7/12-2/15) /(0,9*(5/8-1/3)*1_5/7)==(13/3)/(5/6+0.25)*3,6*(7/12+1/9)*(7/12-2/15) /(0,9*(5/8-1/3)*(12/7))= 10