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в треугольнике 1 сторона на х см больше, чем 2 сторона и на 5 см меньше, чем 3 сторона длина 2 стороны равна 10 см составте буквенное выражение найдите периметр треугольника если х=7
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Предмет:
Математика -
Автор:
wilsond4f8 - 5 лет назад
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Ответы 1
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пусть будет треугольник АВС.АВ= 1 сторона,ВС= 2 сторона,АС= 3 сторона, тогдаВС= 10смАВ= 10+хАС=(10+х)+5=10+5+х=15+хР=АВ+ВС+АС10+(10+х)+(15+х)=35+2х35+2*7=35+14=49см
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Автор:
baileydo0q - 1 год назад
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3
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