Вычислить (2a+c)(a-b), если a={4,-2,3} b={1,-2,0} c={2,1,-3}

(2a + c)(a - b)1) a = 4; b = 1; c = 2        (2a+c)(a-b) = (8+2)(4-1) = 10*3 = 302) a = -2; b = -2; c = 1      (2a+c)(a-b) = (-4+1)(-2+2) = -3*0 = 03) a = 3; b = 0; c = -3       (2a+c)(a-b) = (6-3)(3-0) = 3*3 = 9