х^6+3x^4-x^2-3=0 Решите уравнение

х^6+3x^4-x^2-3=0
Решите уравнение
- Предмет:
  Математика
- Автор:
  cleopatradean
- 5 лет назад

Ответы 2

$x^6+3x^4-x^2-3=0 \\ x^2(x^4-1)+3(x^4-1)=0 \\ (x^2+3)(x^4-1)=0 \\ \\ x^2+3 eq 0 \\ x^4-1=0 \\ x^4=1 \\ x=1 \\ x=-1$ Ответ: x=-1, x=1.
- Автор:
  carleighoevh
- 5 лет назад
- 0
x^2=tt^3+3t^2-t-3=03:+-1,+-3t=1 1^3+3*1^2-1-3=0t1=1 x1=-1 x2=1деление на картинкеt^2+4t+3=0d=16-12=4t2=-3 (корень не действителен, т.к квадрат числа не может быть равен отрицательному числу)t3=-1 (корень не действителен, т.к квадрат числа не может быть равен отрицательному числу)Ответ: x1=1 x2=-1
- Автор:
  jacqueline
- 5 лет назад
- 0
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х^6+3x^4-x^2-3=0 Решите уравнение

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х^6+3x^4-x^2-3=0
Решите уравнение