(4x-12)(3+4x+x^2)/(x^2+2x+1)(9-x^2) Прошу,срочно!

(4x-12)(3+4x+x^2)/(x^2+2x+1)(9-x^2) 1)3+4x+x^2 = 0 D = 16 - 12 = 4x1 = -3, x2 = -1(x+3)(x+1)4(x-3)(x+3)(x+1)/(x+1)^2 *(- (x-3)(x+3))= -(4/x+1)