3log^2√2x-14log√2x-5=0помогите решить

Решение3log^2√2x-14log√2x-5=0ОДЗ:  x > 0log√2x = t3t² - 14t - 5 = 0D = 196 + 4*3*5 = 256t₁ = (14 - 16)/6 = - 1/3t₂ = (14 + 16)/6 = 51)  log√2x = - 1/3x = (√2)⁻¹/³x = 1/(2)¹/⁶2)   log√2x = 5x = (√2)⁵x = √(2⁵) = 4√2