Решите уравнение: 2cos^2 x=1+sin x

2-2sin^2 x-2-sin x=0-2sin^2 x-sin x=02sin^2 x+sin x=0sin x(2sin x+1)=0sin x=0 x=pi/2+2pin2sin x+1=0sin x=-1/2x=-pi/6+pin