решить: x[tex] x^{6}-7x^{3} -8=0[/tex]

x^6 - 7x^3 - 8 = 0 x^3 = t ==>t^2  - 7t - 8 = 0 D = 49 + 32 = 81 = 9^2t1 = ( 7 + 9)/2 = 8t2 = ( 7 -  9)/2 = - 1x^3 = 8 x = 2x^3  = - 1x = - 1 Ответ- 1 ; 2