x^2-y^2= -5
2x+y=1
це система

y = 1 - 2x X^2 - ( 1 - 4x + 4x^2 ) = - 5 X^2 - 1 + 4x - 4x^2 + 5 = 0 - 3x^2 + 4x + 4 = 0 D = 16 + 48 = 64 = 8^2 X1 = ( - 4 + 8 ) : ( - 6 ) = - 2/3 X2 = ( - 12 ) : ( - 6 ) = 2 y = 1 - 2x y1 = 1 + ( 4/3 ) = 2 1/3 y2 = 1 - 4 = - 3 Ответ ( - 2/3 , 2 1/3 ) ; ( 2 ; - 3 )