2sin^²-9sin x+4=0 решите плиз

sin²(4x)-cos²(4x)=0sin²(4x)-(1-sin²4x)=02sin²4x-1=0sin²4x=1/2sin4x=1/2   sin4x=-1/24x=π/4+π*nx=π/16+π*n/4