решите неравенство: 1)2x^2-5x+2<0
2)6x^2+x-1>0

1)2x^2 - 5x +2x<02x^2 -5x +2x = 0a=2 b= -5 c = 2D = b^2 -4ac = 25 - 4 * 2 * 2 = 25 - 16 = 9√ D = 3x = b+- √D/2ax1 = -5 + 3 / 2 *2 = -2 /4 = - 0.5 x2 = -5 - 3/2*2 = -8 / 4 = -2Ответ; ( -2 ; -0.5)2)6x^2 +x -1 > 02х^2 + x - 1 = 0a= 2 b = 1 c = -1D = b^2-4ac = 1 + 4 * 2 * (-1) = 9√D =3 x= b +- √D / 2a x1= 1 + 3 / 2*2 = 4/4 = 1x2= 1-3 / 2*2 = -2 /4 = -0.5Ответ: х c ( - бесконечность ; -0.5 ) U ( 1 ; + бесконечность)