Найти производную сложной функции : y=(cos2x)^arctg√xln(y)= ln((cos2x)^arctg√x)(1/y)·y⁽¹⁾=[ln((cos2x)^arctg√x)]⁽¹⁾y⁽¹⁾=y·[(arctg√x)·ln(cos2x)]⁽¹⁾y⁽¹⁾=[(cos2x)^arctg√x]·[{(arctg√x)}⁽¹⁾·ln(cos2x)+(arctg√x)·{ln(cos2x)}⁽¹⁾]y⁽¹⁾=[(cos2x)^arctg√x]··[{1/(1+x)}·(1/(2√x))·ln(cos2x)+(arctg√x)·{1/(cos2x)}·(-sin2x)·2]==[(cos2x)^arctg√x]·{ln(cos2x)/(2(√x)(x+1))-2·(sin2x)·(arctg√x)/cos2x}