1+sin^2x+cosx=0
Хелп плз(

1+sin^2x+cosx = 0 1+1-cos^2x+cosx = 0cos^2x-cosx-2 = 0cosx = t, cos^2x = t^2, -1≤t≤1t^2-t-2 = 0D = 1+4*2 = 9t1 = -1t2 = 2 - не подходит.cos x = -1x = П+2Пn, n∈Z