f(x)= (x+1)(x+2)(x+3)
Найти f'(х)

ф(х)=(х^2+2х+х+2)(х+3)ф(х)=(х^2+3х+2)(х+3)ф(х)=х^3+3х^2+3х^2+9х+2х+6ф(х)=х^3+5х^2+11х+6ф'(х)=3х^2+10х+11