Решите в целых числах уравнение 2xy-3x+10y=32

x(2y-3) + 5(2y - 3) = 17(x+5)(2y - 3) =171) x + 5 = 1 => x = -42y - 3 = 17 => y = 102) x+5 = -1 => x = -62y - 3 = -17 => y = -73) x+5 = 17 => x=122y-3 = 1 => y = 24) x+5 = -17 => x = -222y - 3 = -1 => y = 1Ответ: (-4; 10), (-6; -7), (12; 2), (-22; 1)