• Решите неравенство [tex]\frac{5x+8}{4-x}\ \textless \ 2 [/tex]

Ответы 1

  • \frac{5x+8}{4-x}\ \textless \ 2, \\ \left \{ {{4-xeq0,} \atop {\frac{5x+8}{4-x}-2\ \textless \ 0;}} ight. \ \left \{ {{xeq4,} \atop {\frac{5x+8-8+2x}{4-x}\ \textless \ 0;}} ight. \ \left \{ {{xeq4,} \atop {\frac{7x}{4-x}\ \textless \ 0;}} ight. \ \left \{ {{xeq4,} \atop {\frac{x}{x-4}\ \textgreater \ 0;}} ight. \   \left \{ {{xeq4,} \atop x(x-4)\ \textgreater \ 0;}} ight. \left [ { \left \{ {{x\ \textless \ 0,} \atop {x-4\ \textless \ 0,}} ight. } \atop { \left \{ {{x\ \textgreater \ 0,} \atop {x-4\ \textgreater \ 0;}} ight. }} ight. \ \left [ { \left \{ {{x\ \textless \ 0,} \atop {x\ \textless \ 4,}} ight. } \atop { \left \{ {{x\ \textgreater \ 0,} \atop {x\ \textgreater \ 4;}} ight. }} ight. \ \left [x\ \textless \ 0, } \atop {x\ \textgreater \ 4; }} ight. \\ x\in(-\infty;0)\cup(4;+\infty).
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