Решить неравенство корень из 3/2cosx+1/2sinx<=корень из 2/2

√3/2cosx+1/2sinx≤√2/2cosπ/6cosx+sinπ/6sinx≤√2/2cos(π/6-x)≤√2/2π/4+2πn≤π/6-x≤7π/4+2πnπ/12+2πn≤-x≤19π/12+2πn-19π/12-2πn≤x≤-π/12-2πnОтвет: [-19π/12-2πn;-π/12-2πn]