Найдите корень уравнения:
5y+7(3-y)=3(5-2y)-6
7y-4(3y+5)=2-3(4y-9)

да

5y+7(3-y)=3(5-2y)-65y+21-7y=15-6y-65y-7y+6y=-21-6+154y=-12y=(-12):4y=-37y-4(3y+5)=2-3(4y-9)7y-12y-20=2-12y+277y-12y+12y=20+2+277y=49y=49:7y=7

5у+21-7у = 15-6у-65у+6у-7у = 15-6-214у = -12у - -37у-12у-20 = 2-12у+277у-12у+12у = 2+27+207у = 49у = 7