Как решить 3sinx - 2cos^x = -3?

3sinx - 2cos²x = -33sinx - 2(1-sin²x) = -33sinx - 2 + 2sin²x = -32sin²x + 3sinx + 1 = 0sinx = t2t² + 3t + 1 = 0D = 9-8 = 1√D = 1x₁ = (-3-1)/4 = -1x₂ = (-3+1)/4 = -1/2sinx = -1sinx = -1/2x = -π/2 + 2πnx = -π/6 + 2πnx = -5π/6 + 2πnn∈Z