Помогите решить уравнение:
1) 3,557+x/2=4;
2) x-0,731/3=5;
3) 12,392+x/5=2,365+2,635;
4) 125,95-x/2,65+4,35=6;
Образец: 4,907+y/3=4; (4,907+y):3=4; 4,907+y=12;
Y=12-4,907; Y=7,093

(3,557 + х ) / 2  = 4(3,557 + х ) : 2  = 43,557 + х  = 4 *23,557 + х = 8х = 8  - 3,557х = 4,443(х-0,731)/3  = 5(х - 0,731) : 3 = 5х - 0,731 = 5*3х  - 0,731 = 15х= 15 + 0,731х =15,731(12,392 + х ) / 5  = 2,365 + 2,635(12,392 +х) :  5 = 512,392+х = 5*512,392 +х = 25х= 25 - 12,392х=12,608(125,95 -х ) /(2,65  + 4,35)  =  6(125,95 - х )  : 7 =6125,95 -х = 6*7х= 125,95 -42х= 83,95