4(n + [tex] \frac{5}{12} [/tex]) = 1 [tex] \frac{1}{6} [/tex](6n - 1[tex] \frac{1}{7} [/tex])
Найти n

4( n + 5/12 ) = 1 1/6 ( 6n - 1 1/7 ) 4( n + 5/12 ) = 7/6( 6n - 8/7 ) 4n + 5/3 = 7n - 4/3 3n = 3n = 1