1)4x/27-x-3/9+x+1/3<0 2)x-x/4>2 и 3x-2>4x-5.6

Ответы 1

1) $\frac{4x}{27}-x-\frac{3}{9}+x+\frac{1}{3}\ \textless \ 0$ $\frac{4x}{27}-\frac{1}{3}+\frac{1}{3}\ \textless \ 0$ $\frac{4x}{27}\ \textless \ 0$ $27*\frac{4x}{27}\ \textless \ 27*0$ $4x\ \textless \ 0$ $x\ \textless \ 0$ 2) $\left \{ {{x-\frac{x}{4}\ \textgreater \ 2} \atop {3x-2\ \textgreater \ 4x-5.6}} ight.$ $\left \{ {{4x-4*\frac{x}{4}\ \textgreater \ 4*2} \atop {3x-4x\ \textgreater \ -5.6+2}} ight.$ $\left \{ {{4x-x\ \textgreater \ 8} \atop {-x\ \textgreater \ -3.6}} ight.$ $\left \{ {{3x\ \textgreater \ 8} \atop {x\ \textless \ 3.6}} ight.$ $\left \{ {{x\ \textgreater \ \frac{8}{3} } \atop {x\ \textless \ 3.6}} ight.$ x∈ $(2\frac{2}{3},$ $3,6)$
- Автор:
  floydbarber
- 5 лет назад
- 0
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