x^2+13x+12=0 решите

x^2 + 13x + 12 = 0 
D = 169 - 48 = 121
x1 = ( - 13 + 11)/2 = - 2/2 = - 1
x2 = ( - 13 - 11)/2 = - 24/2 = - 12

x^2+13x+12=0
D=b^2-4ac=169-4*12=121
x1=-b+кореньD разделить на 2a=-13+11/2=-1
x2=b-кореньD /2а=-13-11/2=-12