[tex] \left \{ {{3x-y=2} \atop { x^{2} -4x+8=y}} ight. [/tex]

3x - y = 2 x^2 - 4x + 8 = y ----------------------y = 3x - 2 3x - 2 = x^2 - 4x + 8 x^2 - 7x + 10 = 0 D = 49 - 40 = 9 = 3^2 x1 = ( 7 + 3 ) : 2 = 5 x2 = ( 7 - 3 ) : 2 = 2 y1 = 3*5 - 2 = 13 y2 = 3*2 - 2 = 4 Ответ ( 5 ; 13 ) ; ( 2 ; 4 )