решите уравнение
(4×b-16)÷2=10
(2+x÷7)×8=72
35÷(15-y÷8)=5
(t×3+5)÷4=8

(4×b - 16) ÷ 2 =  104b - 16  = 10×24b  - 16 = 204b=20 +164b=36b=36÷4b=9проверим:(4*9 -16)÷2 =10(36-16)÷2=1020÷2 = 1010=10(2+х÷7)× 8 =722+х÷7  = 72÷82+х÷7 = 9х÷7 = 9-2х÷7 = 7х=7*7х=49(2+49÷7)×8=72(2+7)×8=729×8 = 7272=7235÷(15 -у÷8) = 515 - у÷8 = 35÷515 - у÷ 8 = 7у÷8 = 15 -7у÷ 8 = 8у=8*8у=6435÷ (15 - 64÷8) = 535÷(15-8) = 535÷ 7 = 55=5(t× 3  + 5)÷ 4 = 83t  + 5  = 8×43t + 5 = 323t = 32-53t = 27t=27÷3t=9(9×3 +5)÷ 4 = 8(27+5)÷ 4 = 832÷4 = 88=8