{xy=5 {x2+y2=26
решите как биквадратное срочно

Х = 5 / у Х^2 = 25 / у^2 Х^2 = 26 - у^2 25 / у^2 = 26 - у^2 25 = у^2( 26 - у^2 ) 25 = 26у^2 - у^4 у^4 - 26у^2 + 25 = 0 y^2 = a ; a > 0 D = 676 - 100 = 576 = 24^2 a1 = ( 26 + 24 ) : 2 = 25 a2 = ( 26 - 24 ) : 2 = 1 y^2 = 25 ==> y1 = 5 ; y2 = - 5 y^2 = 1 ==> y3 = 1 ; y4 = - 1 X = 5 / y X1 = 5 : 5 = 1 X2 = 5 : - 5 = - 1 X3 = 5 : 1 = 5 X4 = 5 : - 1 = - 5 Ответ ( 1 ; 5 ) ; ( - 1 ; - 5 ) ; ( 5 ; 1 ) ; ( - 5 ; - 1 )