Найдите корни уравнения (2,5y-4)*(6y+1,8)=0 htibnt g; jxtym ye;yj
 

(2,5y-4)*(6y+1,8)=01) 2,5y - 4 =02,5y = 4y = 4 / 2,5y1= 1,62) 6y+1,8 = 06y = -1,8y= -1,8 / 6y2 = -0,3____________________ (2,5*1,6 - 4)(6*2,5 + 1,8) = 00* (6*2,5 + 1,8) = 0------------------------------(2,5*(-0,3) - 4)*(6*(-0,3) + 1,8) =0(2,5*(-0,3) - 4)* 0 = 0