решите уравнения 3(2x-1)+19=5(x-1)+19
10-2(3y+5)=4(y-2)
7(z-5)+1=2-3(2z-1)

3(2x-1)+19=5(x-1)+19(6x-3)+19=(5x-5)+196x-3+19=5x-5+196x+16=5x+146x-5x=14-16x= -2*************10-2(3y+5)=4(y-2)10-(6y+10)=4y-810-6y-10=4y-8-6y = 4y-8-6y-4y = -8- 10y = - 8y = (-8):(-10)y = ⁸/₁₀y = 0,8*************7(z-5)+1=2-3(2z-1)(7z-35)+1=2-(6z-3)7z-35+1=2-6z+37z-34=-6z+57z+6z=5+3413z = 39z = 39:13z = 3