стороны основания прямого параллелепипеда равны 6 и корень из 3 и образуют угол в 30. Меньшая диагональ параллелепипеда равна корень из 42. какой угол составляет эта диагональ с плоскостью основания?

стороны основания прямого параллелепипеда равны 6 и корень из 3 и образуют угол в 30. Меньшая диагональ параллелепипеда равна корень из 42. какой угол составляет эта диагональ с плоскостью основания?
- Предмет:
  Математика
- Автор:
  owen69
- 6 лет назад

Ответы 1

меньшая диагональ основания BD (по т. косинусов)BD=36+3-2·6·√3·cos30°=36+3-36=3Находим угол между меньшей диагональю пар-даB1D и меньшей диагональю основания BD. Из прямоугольного треугольника В1ВДcos∠В1ДВ=ВД/В1Д cos∠В1ДВ=3/42=1/14∠В1ДВ=arccos1/14
- Автор:
  thelma
- 6 лет назад
- 0
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