Решите плез :з 
Уравнение. 


а) 2,3х-11,2/0,7 = 1,7х-9,4/ -2,1
б) 0,4*(6х-7)=0,5*(3х+7)
в)1/12у-1/9у-1/4у=1 2/3
г) 3/7 - 1/4х = 5 3/7-4х

Спасибо

а) 2,3х-11,2/0,7 = 1,7х-9,4/ -2,12,3х-16 = 1,7х- ⁹⁴/₁₀: (-²¹/₁₀)2,3х-16 = 1,7х- ⁹⁴/₁₀ × (-¹⁰/₂₁)2,3х-16 = 1,7х- (-⁹⁴/₂₁)2,3х-16 = 1,7х + ⁹⁴/₂₁2,3х-1,7x = 16 + 4¹⁰/₂₁0,6x = 20¹⁰/₂₁x = 20¹⁰/₂₁ : 0,6x = 20¹⁰/₂₁ : ⁶/₁₀x = 20¹⁰/₂₁ × ¹⁰/₆x = ⁴³⁰/₂₁ × ¹⁰/₆x = ⁴³⁰ˣ¹⁰/₂₁ₓ₆x = ⁴³⁰⁰/₁₂₆x = 34¹⁶/₁₂₆x = 34⁸/₆₃б) 0,4×(6х-7)=0,5×(3х+7)2,4х-2,8 =1,5х+3,52,4х-1,5x =3,5 + 2,80,9x = 6,3x = 6,3 : 0,9x = 7в)¹/₁₂у-¹/₉у-¹/₄у=1²/₃³/₃₆у-⁴/₃₆у-⁹/₃₆у=⁵/₃³⁻⁴⁻⁹/₃₆y = ⁵/₃-¹⁰/₃₆y = ⁵/₃-y = ⁵/₃ : ¹⁰/₃₆-y = ⁵/₃ × ³⁶/₁₀-y = ⁵ˣ³⁶/₃ₓ₁₀-y = ¹²/₂-y = 6y = - 6г) ³/₇ - ¹/₄х = 5³/₇-4х-¹/₄x + 4x = 5³/₇ - ³/₇3³/₄x = 5x = 5 : 3³/₄x = 5 : ¹⁵/₄x = ⁵/₁ × ⁴/₁₅x = ⁵ˣ⁴/₁₅ₓ₁x = ⁴/₃x = 1¹/₃