Решите уравнение:7 (2y-2)-2(3y-3,5)=9 и 21,5(3х-1)+132,4=(2,8-4х)*0,5

7(2у-2)-2(3у-3,5)=914у-14-6у+7=914у-6у=9-7+148у=16у=16/8у=221,5(3х-1)+132,4=(2,8-4х)*0,564,5х-21,5+132,4=1,4-2х64,5х+2х=1,4-132,4+21,566,5х=-109,5х=-109,5/66,5х=-1 430/665=-1 86/133