Реши уравнение:
3y^2+9y−(y+3)=0

3у^2+9y-(y+3) = 03y^2+9y−y-3=03y^2+8y- 3 = 0D= 64 + 4*3*3= 64 + 36= 100x1 = -8-10/6= -18/6= -3x2 = -8+10/6= 2/6= 1/3