Решите уравнение
[tex] \frac{5}{9} x+3*( \frac{1}{27} x-4)=1 \frac{1}{9} [/tex]



помогите

5/9х + 3 * (1/27х - 4) = 1 1/95/9х + 3/27х - 12 = 1 1/95/9х + 1/9х = 1 1/9 + 126/9х = 13 1/92/3х = 118/9х = 118/9 : 2/3х = 118/9 * 3/2х = 59/3х = 19 2/3Ответ: 19 2/3.