1+2log(x+5) 5=log5(x+5)

1+2log(x+5) 5=log5(x+5)ОДЗ x>-5x≠-4loga b = 1/logb a1+2log(x+5) 5=1/log(x+5) 5log(x+5) 5+2log²(x+5) 5=1log(x+5) 5 = t2t²+t-1=0D=1+8=9t12=(-1+-3)/4= -1 1/2t=-1log(x+5) 5 = -11/(x+5)=55x+25=1x=-24/5=-4.8t=1/2√(x+5)=5x+5=25x=20ответ -4.8 20