Для каждого значения параметра b решите уравнение
3x-|bx-2|=0

3x = |bx-2|=> x ≥ 01) bx - 2 = 3x, x ≥ 2/b (b≠0)(b - 3)x = 2x = 2/(b-3), b≠32) 2 - bx = 3x, x < 2/b(3+b)x = 2x = 2/(b+3), b≠ -33) b = 03x -2 = 0x = 2/34) b = 33x = -3x + 26x = 2x = 2/6 < 2/3 - подходит5) b = -33x = -3x - 26x = -2x = -1/3 > -2/3 - подходитОтвет: b = 0 => x = 2/3b = -3 => x = -1/3b = 3 => x = 1/3x = 2/(b-3), x ≥ 2/b, b ≠3x = 2/(b+3), x < 2/b, b≠-3