sin3x=cosx-sinx решите плиз

sin3x+sinx=cosx2sin2xcosx-cosx=0cosx*(2sin2x-1)=0cosx=0⇒x=π/2+πk,k∈zsin2x=1/2⇒2x=π/6+2πk U 2x=5π/6+2πk⇒x=π/12+πk,k∈z U x=5π/12+πk,k∈z