помогите пожалуйста
1) Решить неравенство: [tex] log _{2} * x^{2}-2x/x-3\ \textless \ 3 [/tex]
2) Решите уравнение: [tex]2^{1+ \sqrt{x} } + 2^{2- \sqrt{x} } =9[/tex]

{(x²-2x)/(x-3)>0{(x²-2x)/(x-3)<81)x(x-2)/(x-3)>0x=0  x=2  x=3          _                 +               _                +------------(0)-------------(2)---------------(3)-----------------0<x<2 U x>32)(x²-2x)/(x-3)-8<0(x²-2x-8x+24)/(x-3)<0(x²-10x+24)/(x-3)<0x²-10x+24=0x1+x2=10 U x1*x2=24⇒x1=4 U x2=6x-3=0⇒x=3           _                +               _                 +----------------(3)------------(4)----------(6)-----------------x<3 U 4<x<6          \\\\\\\\\\\\\\\\                \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\---------(0)---------(2)----------(3)-----------(4)----------------(6)----------//////////////////////////////////////////                     ////////////////////x∈(0;2) U (4;6)22*2^√x+4/2^√x-9=0,x≥02√x=a2a+4/a-9=02a²-9a+4=0D=81-32=49a1=(9-7)/4=1/2⇒2^√x=2^-1⇒√x=-1 нет решенияf2=(9+7)/4=4⇒2^√x=4⇒√x=2⇒x=4