Решите уравнение:
ctg^2*x + 3sinx+1 = (1/sin^2x) +3

cos^2*x/ sin^2*x +3sinx +1 = 1/ sin^2*x +3( cos^2*x - 1) /sin^2*x +3sinx - 2 =0- sin^2*x / sin^2*x +3sinx - 2 =0- 1 +3sinx -2 = 03 sinx = 3sinx = 1x = п/2 + 2пn? n принадлежит Z