(3/2-корень 3/2і)^6/6× е^-і п/3

a⁶/6ba = 3/2 - i√3/2|a| = √(9/4 + 3/4) = √(12/4) = √3a = √3(cos(π/6) - i*sin(π/6)) = √3e^(-iπ/6)a⁶ = 27e^(-iπ)a⁶/6b = 27e^(-iπ)/(6e^(-iπ/3)) = 4,5e^(-2πi/3)Ответ: 4,5e^(-2πi/3)