1)[tex] \sqrt{2x+1} = \sqrt{ x^{2} -2x+4}[/tex]
2)[tex] \sqrt{x} = \sqrt{ x^{2} -x-3} [/tex]
3)[tex] \sqrt{x+2} = \sqrt{2x-3} [/tex]
4)[tex] \sqrt{9- x^{2} } = \sqrt{x+9} [/tex]

1) ОДЗ: х ≥ -0,52x + 1 = x² - 2x + 4x² - 4x + 3 = 0(x - 3)(x - 1) = 0x₁ = 1; x₂ = 32) х ≥ 0x = x² - x - 3x² - 2x - 3 = 0(x - 3)(x+1) = 0x₁ = -1 - не подходитx₂ = 3Ответ: 33) x ≥ - 2x + 2 = 2x - 3x = 54) ОДЗ: [-3; 3]9 - x² = x + 9x² + x = 0x₁ = 0x₂ = -1