решите log1/3(x²-5x+33)= -3

x^2-5x+33=(1/3)^(-3)x^2-5x+33=27x^2-5x+6=0D=25-4*1*6=1x1=(5-1)/2=2x2=(5+1)/2=3

log1/3(x²-5x+33)= -3(1/3)^-3=1/(1/3)^3=1/(1/27)=27x^2-5x+33=27x^2-5x+6=0D=(-5)^2-4*1*6=1x₁=(5+√1)/2=3x₂=(5-√1)/2=2Ответ: х₁=3            х₂=2