Найдите решение уравнения: cos²x = cos x + 2

cos^2 (x) - cos (x) -2 =0w =cos (x)a*w^2 +b*w +c = 0 | кореньw1 = |d -b / 2aw2 =-|d-b/2ad=b^2 -4*a*c a=1 b=-1 c=-2то w1=2 w2=-1cos (x)=wx=Пn+acos (w)x=Пn+acos (w)-П ( пи )х1=Пn+acos (w1)x1=Пn+acos (2)x2=Пn+acos (w2)x2=Пn+acos(-1)x2=Пn+Пх3=Пn+acos (w1)-Пх3=Пn-П+acos (2)x4=Пn+acos (w2)-Пх4=Пn+acos (-1)x4 = Пnx1 = Пx2=-K (acos(2)) +2П-iJ (acos (2))x3=K (acos (2))+iJ (acos (2))