решите систему
x^3-y^3=6
x-y=2

(x-y)(x^2+xy+y^2)=6x-y=2x^2+xy+y^2=3x=2+yy^2+4y+4+y^2+2y+y^2=33y^2+6y+1=0D=24y1,2=(-5+-sqrt(24))/6x1=2+(-5+sqrt(24))/6x2=2+(-5-sqrt*24))/6