cos^2x-10sinx+10=0
Помогите

Cos^2x-10sinx+10=0Cos^2x = 1 - Sin^2x1 - Sin^2x - 10Sinx + 10 = 0-Sin^2x - 10Sinx + 11 = 0t = Sinx ∈ [-1;1]-t^2 - 10t + 11 = 0D = 100 - 4 * (-1) * 11 = 144 t1 = (10 + √144) / -2 = -11 ∉ [-1;1]t2 = (10 - √144) / -2 = 1Sinx = 1 => x = π/2 + 2πn, n ∈ Z