sin x + cos^2x=5\4 решить

sin x + 1 - sin²x = 5/44sin²x - 4sinx + 1 = 0sin x = t4t² - 4t + 1 = 0D = 16 - 16 = 0t = 4 / 8 = 1/2sin x = 1/2x = (- 1)ⁿarcsin (1/2) + πn, n∈Zx = (- 1)ⁿ · π/6 + πn, n∈Z