sin2x=корень из 3 sin(3п/2+x)

sin2x=√3sin(3π/2+x)sin2x=√3(-cosx)2sinxcosx+√3cosx=0cosx*(2sinx+√3)=01)cosx=0x=π/2+πk2)2sinx+√3=0sinx=-√3/2x=(-1)^(k+1)π/3+πk;k€Z