Решите пожалуйста
sin3x=-1

sin3x = sin(2x + x) = sin2x*cosx + cos2x*sinx = 2sinx*cos^2x + cos2x*sinx2sinx*cos^2x + cos2x*sinx - sinx = 0sinx(2cos^2x + cos2x - 1) = 0sinx = 0; x = pik, k прин Z2cos^2x + cos2x - 1 = 01 + cos2x + cos2x - 1 = 02cos2x = 0cos2x = 02x = pi/2 + pik, k прин Zx = pi/4 + pik/2, k прин Z