Найдите общий вид первообразных:
f(x) = 2x + cos x

f(x) = [tex] (5x - 3)^{2} [/tex]

f(x) = [tex] \frac{1}{(10x + 2)^2} [/tex]

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F(x)+ 2x^2/2 + sinx = x^2+sinx +CF(x)=(5x-3)^3 / 3 * (5x-3)'= 5*(5x-3)^3/3f(x)=(10x+2)^-2F(x)=(10x+2)^-1/-1 *(10x+2)' = -10*(10x+2)^-1